(x+5)(x+5)=x^-25

Solution for (x+5)(x+5)=x^-25 equation:

(x+5)(x+5)=x^-25

We move all terms to the left:

(x+5)(x+5)-(x^-25)=0

We get rid of parentheses

(x+5)(x+5)-x^+25=0

We multiply parentheses ..

(+x^2+5x+5x+25)-x^+25=0

We add all the numbers together, and all the variables

(+x^2+5x+5x+25)-1x+25=0

We get rid of parentheses

x^2+5x+5x-1x+25+25=0

We add all the numbers together, and all the variables

x^2+9x+50=0

a = 1; b = 9; c = +50;
Δ = b2-4ac
Δ = 92-4·1·50
Δ = -119
Delta is less than zero, so there is no solution for the equation